How many knights can you place on a chess board so that none of them are able to attack any of the others? (Knights move in an 'L' shape, two spaces in one direction then one space sideways.) Can you find a nice proof that it is impossible to do more than your number?
26 comments:
I think that 16 knights can fit on a chess board without blocking another ones space because if you put two L's together it makes a rectangle, or one eighth of the board. If you put another rectangle on top of the other one it equals one fourth of the board. The equation would be; 4 knights (per 1/4 of the board) × 4 sections(of the board)= 16 knights in all. By the way, a chess board is 8 squares by 8 squares!
I think 33 knights is the maximum amount you can fit on a chess board without any of them in danger. In the first row you put 5 on black squares than on the other 7 rows you put 4 on the black squares. 7x4=28, 28+5=33.
-Leo
according to what i have found only 16 can fit on the chess board without eating each other, because the chess board is 8by8 squares. And each knight will have to take at least 4 squares to be able to move, and 8x8=64. and then 64 divided by 4=16. so that is my theory, my equation.
When you move a knight, he will always land on the opposite colour square he started off on. For example:
if you start on a white, you will end up on a black,
So if you put a knight on every white square on the board, you could move any knight once without attacking.
-Ben
I forgot to add that 32 knights can fit on a chess board without attacking each other LOL
-Ben
I think the maximum number of knights on a chess board is 24because if you put 8 knights on 2 of the coloums on the oppisite sides of the boards all the way on the left and on the right there is 16 knights on the board.This blocks the 2 coloums next to the coloums full coloums with knights. Then you can put a 4 square square in the middle of the board. then put a 2 square rectangle in the bottom of the 2 middle coloums and another 2 square on the top of the middle 2 coloums. the middle coloums equal up to 8 so 8+16=24
I am not sure, even though Iris and Adele had valid equations I was able to fit 33 knights on a chess board.
Hey everyone,
After a LONG time of displaying it on a chess boards that I made on Microsoft Excel, I found that 32 knights can fit without attacking each other. I'm not really sure how to explain this so I'll try my hardest. I started by placing a couple of knights, and marking the fields that they attacked. On each chessboard I added more and more knights. I placed them vertically, horizontally, and diagonal. I found with diagonal, there is a pattern. One diagonal of knights, the next one of x's or fields attacked. I was really surprised to find that it worked. A cool thing is that the my last chess board with the diagonal patterns, had 32 fields attacked and 32 knights could be placed on it. Cool, huh?
~ Katty
Hey everyone,
It's me again! I just wanted to say that Ben's theory works. I tried it and it works and I agree with it 100%.
~Katty
You should be able to 32 knights on every white square, (1 on each) and it will be good because as it says in Ben’s theory if you only do 1 move it will only reach a black square. However if you 2 moves it does not work.
If you put all the knights in the corners than you can only have 4 knights. all the other places aer dangerus.
Ben's theory is right except you could also move it to every black square
I think that 32 knights could fit onto the board
I assume that it is for one turn.So the max is 32 knights because the way a knight moves means that it has to land on a square of the opposite color.So Bens theory is correct.So the answer is 32.
-Your Friendly Neighborhood Spiderman
You put 1 knight in every other square. By placing one in every other square, you are leaving places around it unpotected as opposed to putting them in a line leaving everything protected. If you do this in every row, then you can put a piece every other space.
i did the experiment twice and i got 16 on the first try and for some reason i got 32 on the 2nd. so to explain, each time a knight moves, it moves four squares and a chess board is 8x8 . 8x8=64 and 64/4=16.so 16 can be put on the board. that is my 16 theory (BTW ADELLE I DID NOT, I REPEAT DID NOT COPY U SO DO NOT ATTACK ME TOMORROW OR ELSE NO MORE MENTOS OR TICTAC)and i have no idea how i got 32 on teh 2nd try so screw that.
P.S
who is kamuka7?!?!?!?!?!? seriously!!!
-Josel The apparent Murderer who will destroy any one who will adress her as that
Sorry,worng answer. the real answer is 32.You can ether put all 32 an black or on white. If you us black and white than the knights will attack each other.
I think that 32 knights can fit on a chess board without attacking each other. They can only be diagonal from each other so that they can’t attack each other. Four knights can be in each row. If you do more than 32 th other knights can be attacked
this is for every one who said it was 32; KNIGHTS CANT MOVE ON A DIAGONAL LINE, ONLY VERTICAL OR HORIZONTAL....
hey its liam and this equation is pretty simple so basically 64 spaces right. you can easily figure it out because you can fit one night on all of one colour. so basically you divide since there are 2 colors and 64 spaces you just divide it by the colors (2) and u get 32: tah dahhh :)
There are 64 sqaures so if its divisible by 2 then 32 knights take 2 squares each without clashing with others. Since the chess board is 8x8, then separate the board into 4x2. Since it = 8 then 4 knights can fit into then without touching each other or attacking each other that makes it so that its
64/2=32. Therefore 32 knights can fit on a 8x8 chessboard without clashing or attaking another knight.
-Emily
I think that you can fit 32 knights on a chess board. That is because you can fit all the knights on a black or white sqaure and you can't attack each other. So if you divide 64(8 by 8) by 2 it gives you 32.
Are u guys sure the max is 32. I fit 33, try putting 5 on the first row instead of four, but I might have screwed up.
(My keyboard is not working that is why i did not use a question mark in my first sentence.
Are u sure the max is 32. Try putting 5 in the first row, maybe I screwed up but I do not think so.
-Leo
i agree with ben. it is 32
you can put a knighit on every other sqare.they wiil not be able to attack eachother.therefore you could have 31 knights.josel the apperant murderer.oops did i post that.$$$$$$EM
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